If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2=130
We move all terms to the left:
12x^2-(130)=0
a = 12; b = 0; c = -130;
Δ = b2-4ac
Δ = 02-4·12·(-130)
Δ = 6240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6240}=\sqrt{16*390}=\sqrt{16}*\sqrt{390}=4\sqrt{390}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{390}}{2*12}=\frac{0-4\sqrt{390}}{24} =-\frac{4\sqrt{390}}{24} =-\frac{\sqrt{390}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{390}}{2*12}=\frac{0+4\sqrt{390}}{24} =\frac{4\sqrt{390}}{24} =\frac{\sqrt{390}}{6} $
| (5/5-p)-(p^2/5-p)=-2 | | -1/6n-1/2=-7/9n+1/3 | | -5/8b-3/16=-1/2b+1/8 | | 1/3y+1=9 | | 2x^2=3+2x | | 1/2a+4=6 | | x^2+15x+98=0 | | 2(m)-1/2=17 | | 6.2h=-3.7 | | 1/6c+4=7 | | (4x/3x-2)+(2x/3x+2)=2 | | 6=•+3m=-12 | | 9x×5x+3x=2x+7/9 | | 8t^2-16t-7=0 | | 2(6x+2)=4(2x+4) | | 0.75/p+3=5.88 | | 8x+2(7x+1)=104+3(x+4) | | (12)/w+9=w+13 | | 0=14+32t+-16t2 | | t=65.1=173.8 | | -3v=-3v-3 | | Y+2/3=y/2+1/9 | | 192x=6 | | 4x-2(x+5)=-5(2x-4)+90 | | 4x-5/3=10 | | 2^3x=100 | | 25x2+20x=-7 | | U2-8u+15=0 | | (X2-3x-10)(x2-5x-6=144) | | -2-3c=7 | | 0.07y+0.5=0.51y+1.2 | | 1/4y-1/8=y/6 |